Worked Solution:
The circle with centre
C( –2, –2) and radius
4 has equation:
(x + 2)2 + (y + 2)2 = 42Substitute
y = 5 into the circle's equation:
(x + 2)2 + (5 + 2)2 = 16
x2 + 4 x + 37= 0Since the
discriminant,
b2 – 4 ac = –132 is negative then there are 0 points on the line that intersect with the circle.