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Polynomials: Differentiation Rules
Using the Chain Rule, differentiate q = ( x – 2 )3
dq
---
dx
 = ( x + ) ( x + )

tickcross


Worked Solution:

The Chain Rule
y = u(v(x))=>
dy
---
dx
 =
du
---
dv
×
dv
---
dx
Here y is q, u = v3 and v = x – 2
=>
du
---
dv
 = 3v 2  and 
dv
---
dx
 = 1
=>
dq
---
dx
 = 3 (x – 2)2(1)
dq
---
dx
 = 3 (x – 2)2

© MEI Produced by Dr Ron Knott, revised 15 May 2007
tom . button [AT] mei . org . uk 		Test reference: PolyDiffRules.html?ref=81157,qu=chain