S | = | 20 e 0.56×12 | ||
= | 20 e 6.720 | |||
= | 20×828.81751 | |||
= | 16576.35 | |||
but we cannot have 0.35 insects | ||||
The population after 12 weeks is 16576 insects |
To find x when S is 800:
S = | 800 | = | 20 e 0.56×x | |
Divide both sides by 20: | ||||
40 | = | e 0.56×x | ||
Take natural logs of both sides: | ||||
ln(40) | = | 0.56 x | ||
3.689 | = | 0.56 x | ||
6.587 | = | x | ||
The population reaches 800 in 6.59 weeks (to 2 dps) |
© MEI Produced by Dr Ron Knott, 1 September 2006![]() | Test reference: ExpModelling.html?ref=31870 |