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Differential Equations: Second Order (Auxiliary Equation with 2 Different Real Roots)

The general solution to
d2p
---
dx2
– 11
dp
---
dx
– 26 p = 0 is
= e
 

 
 
+ e
 

 
 

tickcross


Worked Solution:

The differential equation is second order, homogeneous and has constant coefficients.
We can therefore use the auxiliary equation: lambda2 – 11 lambda – 26 = 0
It factorises: (lambda + 2) (lambda – 13) = 0
The two roots of the auxiliary equation are –2 and 13
The general solution is
p = A e – 2 x + B e13 x where A and B are arbitrary constants.



© MEI Produced by Dr Ron Knott, 5 April 2007
tom . button [AT] mei . org . uk
Test reference: DEorder2a.html?ref=99403