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Algebra: Form and Solve Quadratic Equations

A rectangular field has a length 10m shorter than its width.
If the area of the field is 121m2 what are its width and length?

width =m    length =m

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Worked Solution

Call the field's length l and its width w
From the question, l = w – 10
The field is rectangular so its area is l×w = (w – 10)w = 121
which expands to give the quadratic equation w2 – 10 w – 121 = 0
Since the discriminant b2 – 4 ac = 584 is not a perfect square, the roots are not integers so we use the formula to find the roots of the quadratic:
If a w2 + bw + c = 0 then w =
b ± √(b2 – 4 ac)
---
2 a
For this question, a = 1, b = –10, c = –121 so the roots are
w =
10 + √(100 + 484)
---
2
= 17.08305 and w =
10 – √(100 + 484)
---
2
= -7.08305

The width is a positive value so the answer is
the width w is 17.083m,
the length l is w – 10 = 7.083m.



© MEI Produced by Dr Ron Knott, revised 4 August 2004
tom . button [AT] mei . org . uk
Test reference: AlgFormSolveQuad.html?ref=30629