Worked Solution:
( c + a )2 = c2 + 2 a c + a2
( c + a )2 + b = c2 + 2 a c + a2 + bWe want to find values for
a and
b to make the line above into
c2 – 12 c – 1We already have the
c2 term so let's look at the
c term:
For the quadratic in the question, the c coefficient is | –12 | which must be equal to the c term above: |
2 a = | –12 |
a = | –6 |
a2 + b = | –1 | : The quadratic given has a constant term of | –1 |
This must equal a2 + b and we now know the value of a = | –6 | a2 = | 36 | : |
 | 36 | + b = | –1 |
b = –37
y = | c2 – 12 c – 1 | = ( | c – 6 | )2 –37 |
The squared term is always positive or zero
the least value of y must be –37 when the squared term is zero: ( | c – 6 | )2 = 0 |
c = | 6 |
The turning point is therefore
(6, –37)