Vectors: Operations
(
–3
0
–1
)
.
(
7
–3
6
)
=
Worked Solution:
The dot product (the scalar product) of two vectors is a
number
(a scalar):
Multiply the
i
components and add it to the product of the
j
and
k
components to get the scalar product:
(
–3
0
–1
)
.
(
7
–3
6
)
=
(–3)×7 + 0×(–3) + (–1)×6 = –27
©
MEI Produced by Dr Ron Knott, revised 31 March 2009
Test reference:
VectorsOp.html?ref=84349,qu=.