Vectors: Operations
(
4
3
–6
)
.
(
1
–4
8
)
=
Worked Solution:
The dot product (the scalar product) of two vectors is a
number
(a scalar):
Multiply the
i
components and add it to the product of the
j
and
k
components to get the scalar product:
(
4
3
–6
)
.
(
1
–4
8
)
=
4×1 + 3×(–4) + (–6)×8 = –56
©
MEI Produced by Dr Ron Knott, revised 31 March 2009
Test reference:
VectorsOp.html?ref=90014