Vectors: Operations
(
2
–3
8
)
.
(
–3
0
–2
)
=
Worked Solution:
The dot product (the scalar product) of two vectors is a
number
(a scalar):
Multiply the
i
components and add it to the product of the
j
and
k
components to get the scalar product:
(
2
–3
8
)
.
(
–3
0
–2
)
=
2×(–3) + (–3)×8×(–2) = –22
©
MEI Produced by Dr Ron Knott, revised 31 March 2009
Test reference:
VectorsOp.html?ref=7573