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Vectors: Magnitude
For points A( –5, 5) and B( –4, 2)
the magnitude of the vector
->
AB
 is to 3 dps.

tickcross


Worked Solution:

The direction vector is
->
AB
 = (change in x from A to B) i + (change in y from A to B) j
= i – 3 j
The magnitude (length) of this vector is √( 12 + (–3)2 ) = √10 = 3.162 to 3 dps.

© MEI Produced by Dr Ron Knott, revised 15 May 2007
tom . button [AT] mei . org . uk 		Test reference: VectorsMag.html?ref=96177