Vectors: Magnitude
For points
A
(
2,
–1,
6
)
and
B
(
8,
–2,
10
)
the magnitude of the vector
AB
is
to 3 dps.
Worked Solution:
The direction vector is
AB
=
(change in x from A to B)
i
+ (change in y from A to B)
j
+ (change in z from A to B)
k
=
6
i
–
j
+ 4
k
The magnitude (length) of this vector is
√( 6
2
+ (–1)
2
+ 4
2
)
= √53 =
7.28
to 3 dps.
©
MEI Produced by Dr Ron Knott, revised 15 May 2007
Test reference:
VectorsMag.html?ref=80805