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Vectors: Angle between two vectors

The cosine of the angle between 4 i + 2 j and –2 i + 2 j is
to 3 dps.

tickcross


Worked Solution:

The dot product (scalar product) of two vectors a and b is :
a.b = |a| |b| cos(α) where α is the angle between the vectors, and also
(p i + q j).(t i + u j) = p×t + q×u
=>cos(α) =
a.b
---
|a| |b|
The two vectors in this question have lengths
|4 i + 2 j| = 4.47214 and | –2 i + 2 j| = 2.82843
The dot product of the two vectors is 4×(–2) + 2×2 = –4
=>cos(α) =
–4
---
4.47214×2.82843
= –0.316 to 3 dps.
Since the angle and its cosine can be measured clockwise or anticlockwise, the answer 0.316 is also correct.


© MEI Produced by Dr Ron Knott, revised 15 May 2007
tom . button [AT] mei . org . uk
Test reference: VectorsAng2.html?ref=13221