a.b = |a| |b| cos(α) where α is the angle between the vectors, and alsoThe two vectors in this question have lengths
(p i + q j + r k).(t i + u j + v k) = p×t + q×u + r×v
cos(α) =
a.b |a| |b|
5.38516 | and | 2.82843 |
![]() | cos(α) = |
| = –0.788 | to 3 dps. |
© MEI Produced by Dr Ron Knott, revised 15 May 2007![]() | Test reference: VectorsAng2.html?ref=364 |