1 | – | 2 | = | –1 | and | 0 | – | 1 | = | –1 |
For each term after the 1st we add on the common difference, | –1 |
so the 17th term will be | –1 | × | (17 – 1) = | –16 | added on to the first term | 2 |
The 17th term is therefore | –14 |
© MEI Produced by Dr Ron Knott, 13 November 2006![]() | Test reference: SeriesAPterms.html?ref=45786,qu=terms |