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Series: Arithmetic Progressions

In the arithmetic series with a common difference of
– 1
---
5
, starting at 6,
the 4th term is

tickcross


Worked Solution

The common difference is
– 1
---
5
so we add this to each term to get the next
starting from a first term of 6:
1234
6
29
---
5
28
---
5
27
---
5
For each term after the 1st we add on the common difference,
– 1
---
5
so the 4th term will be
– 1
---
5
×(4 – 1) =
– 3
---
5
added on to the first term 6
The 4th term is therefore
27
---
5
= 5.4


© MEI Produced by Dr Ron Knott, 13 November 2006
tom . button [AT] mei . org . uk
Test reference: SeriesAPterms.html?ref=65185