Geometry: Coordinates and Gradients
The distance between
A
(
3,
4
)
and
B
(
–3,
–4
)
is
to 3 dps
Worked Solution
By the Pythagoras Theorem, the distance
AB
is
√((B
x
-A
x
)
2
+ (B
y
-A
y
)
2
)
= √( ((–3) – 3)
2
+ ((–4) – 4)
2
)
= √((–6)
2
+ (–8)
2
)
= √100
= 10
to 3 dps.
©
MEI Produced by Dr Ron Knott, 28 April 2004
Test reference:
GeomCoordsGrads.html?ref=46163,qu=dist
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