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Geometry: Equation of a Circle
The circle with equation (x – 5)2 + (y – 8)2 = 14 has
its centre at (,) and its radius is

tickcross


Worked Solution:

The circle with centre at ( 0, 0 ) and radius r has equation x2 + y2 = r2.
Replacing x by x – 5 and y by y – 8 moves the centre to (5, 8):
(x – 5)2 + (y – 8)2 = r2 = 14
r2 = 14 implies r = √14 = 3.742 to 3 dps.

© MEI Produced by Dr Ron Knott, revised 3 April 2007
tom . button [AT] mei . org . uk 		Test reference: GeomCircleEqun.html?ref=130,qu=simple