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Complex Numbers: Multiplication
( 8 – 4 j ) ( –3 – j ) = + j

tickcross



Worked Solution:

( 8 – 4 j ) ( –3 – j )
= 8 ( –3 – j) –4 j( –3 – j)
= –24 – 8 j + 12 j + 4 j2   but j2 = –1:
= –24 + 4 j – 4
= –28 + 4 j

AS Further Pure Mathematics (MEI Structured Mathematics FP1) Third Edition (2004) pages 46-50
© MEI Produced by Dr Ron Knott, 16 March 2004
tom . button [AT] mei . org . uk 		Test reference: ComplexMult.html?ref=12566